Single Choice

$$2.76\ g$$ of silver carbonate on being strongly heated yields a residue weighing:

A$$2.16\ g$$
Correct Answer
B$$2.48\ g$$
C$$2.32\ g$$
D$$2.64\ g$$

Solution

When silver carbonate is strongly heated, a residue of silver is obtained.
The reaction is as follows:

$$Ag_2CO_3(s)\xrightarrow {Heat} 2Ag(s)+CO_2(g)+\frac {1}{2}O_2(g)$$.

The molecular weight of silver carbonate and silver is $$276$$ g/mol and $$108$$ g/mol respectively.

Thus, when $$276$$ g (or $$1$$ mole) of silver carbonate is heated, $$2\times 108=216$$ g ($$2$$ moles) of silver is obtained.

When $$2.76$$ g of silver carbonate is heated, the amount of residue (silver) obtained is $$\dfrac {216}{276}\times 2.76=2.16$$ g.

Hence, the correct option is $$A$$

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