Subjective Type

$$2S_2O^{2-}_3\,(aq)+I_2(s)\rightarrow S_4O^{2-}_6(aq)+2I^{-}(aq)$$ $$S_2O^{2-}_3(aq)+2Br_2(l)+5H_2O(l)\rightarrow 2SO^{2-}_4(aq)+4Br^{-}(aq)+10H^{+}(aq)$$ Why does the same reductant, thiosulphate react differently with iodine and bromine?

Solution

Bromine is stronger oxidizing agent. Hence, it oxidizes $$\displaystyle S_2O_3^{2-} $$ to $$\displaystyle SO_4^{2-} $$.
Iodine is a weaker oxidizing agent. Hence, it oxidizes $$\displaystyle S_2O_3^{2-} $$ to $$\displaystyle S_4O_6^{2-} $$.

SIMILAR QUESTIONS

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Redox Reactions

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Redox Reactions

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Redox Reactions

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