A beam of light of wavelength $$600 \ nm$$ from a distant source falls on a single slit $$1.00 \ mm$$ wide and the resulting diffraction pattern is observed on a screen $$2 \ m$$ away. The distance between the first dark fringe on either side of the central maxima is :
Condition for obtaining $$m^{th}$$ order minima is
$$a sin\theta=m\lambda$$
Thus for obtaining first diffraction minima,
$$ a sin\theta=\lambda$$
$$\implies sin\theta=\dfrac{600\times 10^{-9}m}{10^{-3}m}\approx tan\theta=\dfrac{y}{D}$$
$$\implies y=1.2\ mm$$
Thus distance between fringes on either side=$$2\times y=2.4\ mm$$
Visible light of wavelength $$6000\times 10^{-8}cm$$ falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at $$60^0$$ from the central maximum. if the first minimum is produced at $$\theta_1$$ then $$\theta_1$$ is close to :
In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is $$6000 A^o$$, then wavelength of first maximum will be
In a Young's double slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single slit diffraction pattern is :
In a double-slit experiment, green light $$(5303\overset{o}{A})$$ falls on a double slit having a separation of $$19.44\ \mu m$$ and a width of $$4.05\ \mu m$$. The number of bright fringes between the first and the second diffraction minima is?
The angular width of the central maximum in a single slit diffraction pattern is $$60^o$$. The width of the slit is $$1$$ $$\mu$$m. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young's fringes can be observed on a screen placed at a distance $$50$$cm from the slits. If the observed fringe width is $$1$$cm, what is slit separation distance? (i.e., distance between the centres of each slit.)
The first diffraction minima due to a single slit diffraction is at $$\theta = 30^o$$ for a light of wavelength 5000 $$\mathring{A}$$. The width of the slit is:
A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength $$5\times 10^{-5}$$ cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is:
A beam of light of $$\lambda = 600 nm$$ from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2m away. The distance between first dark fringes on either side of the central bright fringe is
For a parallel beam of monochromatic light of wavelength $$'\lambda'$$, diffraction is produced by a single slit whose width 'a' is of the order of the wavelength of the light. If 'D' is the distance of the screen from the slit, the width of the central maxima will be
At the first minimum adjacent to the central maximum of a single - slit diffraction pattern, the phase difference between the Huygen's wavelet form the edge of the slit and the wavelet from the midpoint of the slit is: