Single Choice

A black body at a temperature of $$227^{\circ}C$$ radiates heat energy at the rate $$5\;cal/cm^2/s$$. At a temperature of $$727^{\circ}C$$, the rate of heat radiated per unit area in $$cal/cm^2$$ will be:

A$$80$$
Correct Answer
B$$160$$
C$$250$$
D$$500$$

Solution

Heat energy per unit time $$R = \sigma AeT^4$$
Thus heat energy per unit area $$R' = \sigma e T^4$$
$$\implies$$ $$\dfrac{R'_2}{R'_1} = \bigg( \dfrac{T_2}{T_1} \bigg)^4$$

Initial temperature of the body $$T_1 =227 ^oC = (227+ 273) K = 500 K$$
Final temperature of the body $$T_2 =727 ^oC = (727+ 273) K = 1000 K$$
$$\therefore$$ $$\dfrac{R'_2}{5} = \bigg( \dfrac{1000}{500} \bigg)^4$$
$$\dfrac{R'_2}{5} = 16$$
$$\implies R'_2 = 80$$ $$cal/cm^2$$


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