Single Choice

A coil of cross-sectional area $$A$$ having $$n$$ turns is placed in a uniform magnetic field $$B$$. When it is rotated with an angular velocity $$\omega$$, the maximum e.m.f. induced in the coil will be

A$$nBA\omega$$
Correct Answer
B$$\dfrac {3}{2}nBA\omega$$
C$$3 nBA\omega$$
D$$\dfrac {1}{2}nBA\omega$$

Solution

Given, a coil of N turns an area A, rotated with angular speed $$\omega$$ in a uniform magnetic field B.
The flux linking to the coil, $$\phi = NBA $$ sin$$(\omega t)$$
Therefore,
Induced EMF, $$E=$$d (NBA sin$$(\omega t))/dt)$$
E= NBA $$\omega $$
Emax= NBA $$\omega$$


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