Single Choice

A colourblind man marry with a daughter of colourblind father, the generation will be

AThere will be no daughter colourblind
BAll sons will be colourblind
CAll daughter will be colourblind
DHalf of the sons will be colourblind
Correct Answer

Solution

$$X^c$$Y
$$X^c$$X
$$X^c$$ Y
$$X^c$$ $$X^c$$X^c$$ $$X^c$$Y
X $$X^c$$X XY
Colourblindness is X-linked recessive disorder and follows criss-cross inheritance.
A colourblind man ($$X^c$$Y) and daughter of the colourblind father ($$X^c$$X) will obtain 1/4 colourblind daughters, 1/4 carrier daughters, 1/4 colourblind sons and 1/4 normal sons. Hence, half of the sons will be colourblind.
So, the correct answer is option D.

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