Single Choice

A conducting circular loop is placed in a uniform magnetic field of $$0.04\ T$$ with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at $$2\ mm/s$$. The induced emf in the loop when the radius is $$2\ cm$$ is

A$$4.8\pi \mu V$$
B$$0.8\pi \mu V$$
C$$1.6\pi \mu V$$
D$$3.2\pi \mu V$$
Correct Answer

Solution

Induced emf in the loop is given by
$$e = -B . \dfrac {dA}{dt}$$ where $$A$$ is the area of the loop.
$$e = -B.\dfrac {d}{dt}(\pi r^{2}) = -B\pi 2r \dfrac {dr}{dt}$$
$$r = 2\ cm = 2\times 10^{-2} m$$
$$dr = 2\ mm = 2\times 10^{-3}m$$
$$dt = 1s$$
$$e = -0.04\times 3.14\times 2\times 2\times 10^{-2} \times \dfrac {2\times 10^{-3}}{1}V$$
$$= 0.32\pi \times 10^{-5}V$$
$$= 3.2\pi \times 10^{-6}V$$
$$= 3.2\pi \mu V$$.


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