Genetics
Choose the correct answer from the alternatives given. A tobacco plant heterozygous for a recessive character is self-pollinated and 1200 seeds are subsequently germinated. How many seedlings would have the parental genotype?
A cross between two tall plants resulted in offspring having few dwarf plants. What would be the genotypes of both the parents?
(b) Tt and Tt Explanation: In the case of TT and Tt; all offspring would be tall (TT, Tt). In the case of option ‘c’ no gene for a dwarf is present, so all offspring will be tall. In the case of option 'd’, one of the parent plants is dwarf, so it is incorrect. In the case of option ‘b’, most of the offspring will be tall and a few will be a dwarf (TT, Tt, tt). Option ‘b’ is the correct answer.
Choose the correct answer from the alternatives given. A tobacco plant heterozygous for a recessive character is self-pollinated and 1200 seeds are subsequently germinated. How many seedlings would have the parental genotype?
Which of the following ketonic compound is the least stable?
If parents have free ear lobes and the offspring has attached ear lobes, then the parents must be
A flower with Tt genotype is cross-pollinated by TT pollens. What will the genotypes of the resulting endosperm and embryo, respectively, be?
In a monohybrid cross, the genotypic ratio of the offspring in $$F_2$$ generation is
In monohybrid cross, what is the ratio of homozygous dominant and homozygous recessive individuals in F$$_{2}$$ generation?
What is the ratio of a progeny of cross between F1 heterozygous and recessive?
In a cross between a pure tall plant with green pod and a pure short plant with yellow pod, how many short plants are produced in $$F_2$$ generation out of 16?
On crossing red and white flowered plants the ratio of red and white flowered plants in F$$_2$$ generation was 60 : 20, then on selfing the heterozygous red flowered plants, the offsprings would be
If 120 plants are produced on crossing pure red and pure white flowered pea plants, then the ratio of offspring will be