Subjective Type

A cylinder rolls without slipping on a horizontal plane surface. If the speed of the centre is $$25\ m/s$$ what is the speed of the highest point?

Solution


The top point will have velocity
$$V=v+r\omega$$,

Since, $$v=25m/s$$ and $$r\omega$$ is the linear velocity of top most point which will be also in $$forward $$ direction so $$added $$ to $$v$$

And as the motion is without slipping so
$$v=r\omega$$ or $$r\omega =v$$
so net velocity ,
$$V=v+r\omega$$

$$=v+v=2v=2\times 25m/s=50m/s$$


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