Single Choice

A galvanometer having a resistance of 8 ohms is shunted by a wire of resistance 2 ohms. If the total current is 1 amp., the part of it passing through the shunt will be :

A0.2 amp
B0.25 amp
C0.8 amp
Correct Answer
D0.5 amp

Solution

Here, $$V_G=V_S$$
so $$I_G G=I_S S$$

or $$(I-I_S)G=I_SS$$

or $$I_S=\dfrac{IG}{G+S}=\dfrac{1\times 8}{8+2}=0.8 A$$


SIMILAR QUESTIONS

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