Single Choice

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :

A1Hz
Correct Answer
B3Hz
C2Hz
D4Hz

Solution

$$V_{max}=a\omega \Rightarrow f=\dfrac{\omega }{2\pi }=\dfrac{V_{max}}{2\pi a}=\dfrac{31.4}{2\pi \times 5}=\dfrac{31.4}{10\pi }= 1Hz$$

SIMILAR QUESTIONS

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What effect occurs on the frequency of a pendulum if it is taken from the earth surface to deep into a mine

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A thin uniform vertical rod of mass $$m$$ and length $$l$$ pivoted at point $$O$$ is shown in the figure. The combined stiffness of the spring is equal to $$k$$. The mass of the spring is negligible. The frequency of small oscillation is:

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The unit 'hertz' is same as.

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