Subjective Type

A person travelling at $$43.2{\text{ km/h}}$$ applies the brake giving a deceleration of $$6.0{\text{ m/}}{{\text{s}}^2}$$ to his scooter. How far will it travel before stopping?

Solution

Initial velocity $$u=43.2\ km/hr =12\ m/s$$
$$u=12\ m/s, v=0$$
$$a=-6\ m/s^2 $$ (deceleration)
Using third law of motion
Distance $$S=\dfrac {v^2 -u^2}{2(-6)}=12\ m$$


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