Number Systems
$$n^2 -1$$ is divisible by $$8$$ , if n is
A positive integer is of the form $$3q+1, q$$ being a natural number. Can you write its square in any form other than $$3m+1$$ i.e., $$3m$$ or $$3m+2$$ for some integer $$m$$? Justify your answer.
By Euclid's division algorithm , $$ a = bq + r $$ where $$ a , b , q , r $$ are non-negative integers and $$ 0 \leq r < b$$.
On putting $$ b = 3$$ and $$r=1$$ we get
$$a = 3q + 1 $$
Squaring both sides
$$\Rightarrow a^2= (3q + 1)^2 $$
$$\Rightarrow a^2 = (3q)^2 + (1)^2 + 2(3q) $$
$$\Rightarrow a^2 = 3(3q^2 + 2q ) + 1 $$
$$ \Rightarrow a^2= 3m + 1 $$ , where $$ m = 4q^2 + 2q $$ is any integer.
Hence, the square of a positive integer iof the form $$3q+1$$ can not be written in any form other than $$3m+1$$
$$n^2 -1$$ is divisible by $$8$$ , if n is
If $$n$$ is an odd integer then show that $${n^2} - 1$$ is divisible by 8
Show that the square of any integer is either of the form $$ 4q$$ or $$4q+1$$ for some integer $$q.$$
Write whether the square of any positive integer can be of the form $$3m+2$$, where $$m$$ is a natural number. Justify your answer.
Show that the square of any positive integer cannot be of the form $$ (6m + 2) $$ or $$ (6m + 5) $$ for any integer $$ m $$ .
Show that the square on any odd integer is of the form $$ (4q + 1) $$ for some integer $$ q $$.
Show that the cube of a positive integer of the form $$ (6q + r) $$ where $$ q $$ is an integer and $$ r = 0 , 1 , 2, 3 , 4 $$ and $$ 5 $$ is also of the form $$ (6m + r) $$.
State Euclid's division lemma and give some examples.
Write whether the square of any positive integer can be of the form $$3m+2$$, where $$m$$ is a natural number. Justify your answer.
Use Euclid's algorithm to find the HCF of $$4052$$ and $$12576$$.