Chemistry Practical
The cation that will not be precipitated by $$H$$_2S$$ in the presence of dil $$HCl$$ is:
A reddish-pink substance on.heating gives off a vapor which condenses on the sides of the test tube and the substance turns blue. If on cooling water is added to the residue, it turns to its original color. The substance is :
Option (C) is correct.
The substance is cobalt chloride crystals.It is a property of $$CoCl_2$$.
Cobalt sulphide dissolves in aqua regia in the same manner as nickel sulphide. When the aqueous solution of the residue obtained after treatment with aquaregia is treated with a strong solution of potassium nitrite after neutralisation with ammonium hydroxide and the solution is acidified with dil. acetic acid, a yellow precipitate of the complex of cobalt named potassium hexanitritocobaltate (III) is formed.
$$CoS + HNO_3 + 3HCl \longrightarrow CoCl_2
+ NOCl + S + 2H_2O$$
$$ CoCl_2
+ 7KNO_2 + 2CH_3COOH \longrightarrow K_3 [Co(NO_2)_ 6] + 2KCl + 2CH_3COOK + NO + H_2O$$
The cation that will not be precipitated by $$H$$_2S$$ in the presence of dil $$HCl$$ is:
A solution containing a group-IV cation gives a precipitate on passing $$H_2S$$. A solution of this precipitate in $$dil.HCl$$ produces a white precipitate with basic $$NaOH$$ solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is:
In Nessler's reagent for the detection of ammonia the active species is:
Reagent S is:
Reagent used in the qualitative analysis of IVth group is
Group reagent for analytic group $$IV$$ is
Precipitate of group $$IV$$ cations takes place when $$H_2S$$ is
In $$IV$$ group analysis, $$NH_{4}OH$$ is added before passing $$H_{2}S$$ gas because:
Mark the correct statement(s)