A screw gauge has least count of $$0.01 mm$$ and there are $$50$$ divisions in its circular scale. The pitch of the screw gauge is :
The pitch of the screw guage is given as:
$$p=least\ count\times no.\ of\ divisions$$
Substitute the values:
$$p=0.01\ mm\times 50$$
$$p=0.5\ mm$$
A micrometer screw gauge has a negative error of $$7$$ divisions. While measuring the diameter of a wire, the reading on the main scale is $$2$$ divisions and $$78th$$ circular scale division, coincides with baseline. The number of divisions on the main scale per centimetre is $$10$$ and the circular scale has 100 divisions. Find the pitch of the screw.
A screw gauge has 50 divisions on its head scale and the head scale moves 0.4 mm when rotated by four fifth of a rotation then find the pitch in mm.