Subjective Type

A small ball rolls horizontally off the edge of a tabletop that is $$1.20 m$$ high. It strikes the floor at a point $$1.52 m$$ horizontally from the table edge. (a) How long is the ball in the air? (b) What is its speed at the instant it leaves the table?

Solution

We adopt the positive direction choices used in the textbook so that equations such as

(a) With the origin at the initial point (edge of table), the $$y$$ coordinate of the ball is given
by $$yy=-\frac { 1 }{ 2 } g{ t }^{ 2 }$$. If $$t$$ is the time of flight and $$y = –1.20 m$$ indicates the level at which the all hits the floor, then
$$t=\sqrt { \frac { 2(-1.20m) }{ -9.80m/{ s }^{ 2 } } } =0.495s.$$
(b) The initial (horizontal) velocity of the ball is $$\vec { v } ={ v }_{ 0 }\hat { i. } $$. Since $$x = 1.52 m$$ is the horizontal position of its impact point with the floor, we have $$x = { v }_{ 0 }t$$. Thus,
$${ v }_{ 0 }=\frac { x }{ t } =\frac { 1.52m }{ 0.495s } =3.07m/{ s }.$$


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