Single Choice

A transverse harmonic wave on a string is described by $$y(x,t) = 3$$sin $$(36t + 0.08x + \dfrac{\pi}{4})$$ where $$x$$ and $$y$$ are in cm and $$t$$ is in $$s$$. Which of the following statement incorrect?

AThe wave is travelling in negative $$x-$$direction.
BThe amplitude of the wave is $$3$$ cm.
CThe speed of the wave is $$20 \,\, m \,\,s^{-1}$$.
DThe frequency of the wave is $$\dfrac{9}{\pi}$$ Hz.
Correct Answer

Solution

The given transverse harmonic wave equation is $$y = 3$$sin $$(36t + 0.018x + \dfrac{\pi}{4})$$ ....(i) As there is positive sign between $$t$$ and $$x$$ terms therefore the given wave is travelling in the negative $$x$$ direction. The standard transverse harmonic wave equation is $$y = a$$sin$$(\omega t + kx + \phi)$$ ....(ii) Comparing (i) and (ii), we get $$a = 3$$cm, $$\omega = 36$$ rad $$s^{-1}, k = 0.018$$ rad $$cm^{-1}$$ $$\therefore$$ Amplitude of wave, $$a = 3$$cm Frequency of the wave, $$\upsilon = \dfrac {\omega}{2\pi} = \dfrac{36}{2\pi} = \dfrac{18}{\pi}$$Hz Velocity $$V = \dfrac{\omega}{k} = \dfrac{36 \,\,rad \,\,s^{-1}}{0.018 \,\,rad \,\,cm^{-1}} = 2000 \,\,cm \,\,s^{-1} = 20 \,\,m \,\,s^{-1}$$


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