Single Choice

Among the following complexes, the diamagnetic complexes are: $$(K) : K_{3}[Fe(CN)_{6}]$$ $$(L) : [Co(NH_{3})_{6}]Cl_{3}$$ $$(M) : Na_{3}[Co(oxalate)_{3}]$$ $$(N) : [Ni (H_{2}O)_{6}]Cl_{2}$$ $$(O) : K_{2}[Pt(CN)_{4}]$$ $$(P) : [Zn(H_{2}O)_{6}](NO_{3})_{2}$$

A$$K,\ L,\ M,\ N$$
B$$K,\ M,\ O,\ P$$
C$$L,\ M,\, O,\ P$$
Correct Answer
D$$L,\ M,\ N,\ O$$

Solution

$$(K) : K_{3}[Fe(CN)_{6}] \rightarrow 3d^5$$, strong field ligand, paramagnetic (because d-orbital has odd no. of electrons)

$$(L) : [Co(NH_{3})_{6}]Cl_{3}\rightarrow3d^6$$strong field ligand, diamagnetic

$$(M) : Na_{3}[Co(oxalate)_{3}] \rightarrow 3d^6$$strong field ligand, diamagnetic

$$(N) : [Ni (H_{2}O)_{6}]Cl_{2} \rightarrow 3d^8$$ weak field ligand, paramagnetic (because weak field ligand do not allow pairing of electrons in the d-orbitals eventually makes it a paramagnetic complex)

$$(O) : K_{2}[Pt(CN)_{4}] \rightarrow 5d^8$$strong field ligand, diamagnetic

$$(P) : [Zn(H_{2}O)_{6}](NO_{3})_{2} \rightarrow 3d^{10}$$ strong field ligand, diamagnetic (because d-orbital is completely occupied)

Except for $$K$$ and $$N$$ all are diamagnetic complexes.

Hence, option C is correct.

SIMILAR QUESTIONS

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