Current Electricity
A copper wire is stretched to make it $$0.5\%$$ longer. The percentage change in its electrical resistance if its volume remains unchanged is:
An electric wire of length $$'l$$ and area of cross-section $$a$$ has a resistance $$R$$ ohm. Another wire of the same material having same length and area of cross section $$4a$$ has a resistance of
we know $$R=\dfrac {\rho l}{a}$$
where a is the area and l is the length of wire
For first wire an $$R=\dfrac {\rho l}{4a}=\dfrac {R}{4}$$ for second wire.
A copper wire is stretched to make it $$0.5\%$$ longer. The percentage change in its electrical resistance if its volume remains unchanged is:
A uniform wire of length $$l$$ and radius $$r$$ has a resistance of $$100\Omega$$. It is recast into a wire of radius $$\dfrac{r}{2}$$. The resistance of new 2 wire will be :
When $$5V$$ potential difference is applied across a wire length $$0.1\ m$$, the drift speed of electron is 2.5 $$\times 10^{-4} ms^{-1}$$. If the electron density in the wire is 8 $$\times 10^{28} m^{-3}$$, the resistivity of the material is close to
The resistance of a wire is $$R$$. It is bent at the middle by $$180^{\circ}$$ and both the ends are twisted together to make a shorter wire. The resistance of the new wire is
The resistance of a 20 cm long wire is 5 $$\Omega$$. The wire is stretched to form a uniform wire of 40 cm length. The resistance now will be :
If a copper wire is stretched to make its radius decrease by $$0.1$$%, then the percentage increase in its resistance is approximately:
If a rod has resistance $$4\Omega$$ and if rod is turned as half circle, then the resistance along diameter is
The resistance if a wire is '$$R$$' ohm. If it is melted and stretched to '$$n$$' times its original length, its new resistance will be:
A wire of resistance $$4\:\Omega$$ is stretched to double its original length. The resistance of the stretched wire would be
In an aluminum (Al) bar of square cross section, a square hole is drilled and is filled with iron (Fe) as shown in the figure. The electrical resistivities of Al and Fe are $$2.7 \times 10^{-8} \Omega$$ m and $$1.0 \times 10^{-7} \Omega$$ m, respectively. The electrical resistance between the two faces P and Q of the composite bar is