Single Choice

An experiment showed that in a lead chloride solution, 6.21 g of lead combined with 4.26 g of chlorine. The empirical formula of this chloride is:

A$$PbCl_2$$
B$$Pb_2Cl_2$$
C$$PbCl$$
D$$PbCl_4$$
Correct Answer

Solution

Element Mass Atomic weight Relative No. of atoms Simplest ratio
Lead 6.21 g 207 6.21/207 = 0.03 0.03/0.03 = 1
Chlorine 4.26 g 35.5 4.26/35.5 = 0.12 0.12/0.03 = 4
Hence, empirical formula is $$PbCl_4$$.


SIMILAR QUESTIONS

Mole Concept

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Mole Concept

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Mole Concept

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Mole Concept

Determine the empirical formula of an oxide of iron which has $$69.9\%$$ iron and $$30.1\%$$ dioxygen by mass.

Mole Concept

The relative number of atoms of elements, $$X$$ and $$Y$$ in a compound is 0.25 and 0.5. The empirical formula of compound is:

Mole Concept

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Mole Concept

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Mole Concept

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Mole Concept

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