Organic Chemistry
Which of the following pairs of compounds are tautomers?
Arrange the following in the increasing order of expected enol content. $$i.$$ $$CH_3COCH_2CHO$$ $$ii.$$ $$CH_3COCH_3$$ $$iii.$$ $$CH_3CHO$$ $$iv.$$ $$CH_3COCH_2COCH_3$$
Order of enol content:
Aldehyde < Ketone < Keto-aldehyde < Diketone $$(iii < ii < i < iv)$$
Enol formation is possible is there is hydrogen on alpha-carbon to carbonyl group. So, enol formation is more likely for ketone compared to aldehyde. Now, in case of a diketone, hydrogen bonding occurs in the enol form which stabilizes it more compared to keto form. So, it is the most stable followed by keto-aldehyde. Then comes ketone and ultimately aldehyde.
Which of the following pairs of compounds are tautomers?
Tautomerism will be exhibited by:
The isomers whose, structures differ mainly in the arrangement of atoms, but which exist in equilibrium are called:
Identify the compound that exhibits tautomerism:
The correct statement regarding a carbonyl compound with a hydrogen atom on its alpha carbon, is :
Which of the following show stable or major form of tautomerism?
Which of the following statements are correct?
Tautomerism is not exhibited by
Tautomerism is exhibited by
Write tautomeric form of phenol.