Single Choice

At Boyle temperature:

Athe effects of the repulsive and attractive intermolecular forces just offset each other
Correct Answer
Bthe repulsive intermolecular forces are greater than the attractive intermolecular forces
Cthe repulsive intermolecular forces are less than the attractive intermolecular forces
D$$b-\displaystyle \frac {a}{RT} > 0$$

Solution

The Boyle temperature is the temperature at which a non ideal gas behaves most like an ideal gas.
At this temperature that the attractive forces and the repulsive forces acting on the gas particles balance out.
Therefore vapor pressure = atmospheric pressure

SIMILAR QUESTIONS

States of Matter - Gas and Liquid

The temperature at which a real gas obeys the ideal gas laws over a wide range of pressure is called:

States of Matter - Gas and Liquid

At moderate pressure, $$Z$$ value of gas is $$1+xp-\dfrac{yp}{T}$$. The Boyle's temperature is:

States of Matter - Gas and Liquid

The virial equation for a real gas is represented as $$ Z = 1 + \left( b - \frac { a } { R T } \right) \frac { 1 } { V _ { m } } + \left( \frac { b } { V _ { m } } \right) ^ { 2 } + \left( \frac { c } { V _ { m } } \right) ^ { 3 } + \dots $$ The Boyle temperatue for the gas is

States of Matter - Gas and Liquid

The temperature at which a real gas obeys the ideal gas laws over a wide range of pressure is called:

States of Matter - Gas and Liquid

The temperature at which the second virial coefficient of a real gas is zero is called :

States of Matter - Gas and Liquid

Pressure remaining the constant, the volume of a given mass of ideal gas increases for every degree centigrade rise in temperature by a definite fraction of its volume at:

States of Matter - Gas and Liquid

The expression for compressibility factor for one mole of a van der Waal's gas at Boyle temperature is?

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