Single Choice

$$A\xrightarrow[]{KOBr}CHBr_{3}$$ Reactant A is:

Aisopropyl alcohol
Correct Answer
Bmethanol
Cethanoic acid
Dn-butyl alcohol

Solution

This is a haloform reaction. When isopropyl alcohol is treated with $$KOBr$$, it is oxidized to methyl ketone and on further oxidation forms a sodium salt of carboxylic acid and bromoform. $$\underset {A , isopropyl alcohol} {CH_3CH(OH)CH_3}\xrightarrow[]{KOBr} \underset {bromoform} {CHBr_{3}} + CH_3COONa + 2KOH$$ Option A is correct.

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