Subjective Type

Calculate the number of coulombs of positive charge in $$250\ cm^{3}$$ of (neutral) water. (Hint: A hydrogen atom contains one pro eight protons.)

Solution

The volume of $$250\ cm^{3}$$ corresponds to a mass of $$250\ g$$ since the density of water is $$1.0\ g/cm^{3}$$. This mass corresponds to $$250/18=14$$ moles since the molar mass of water is $$18$$. There are ten proton (each with charge $$q=+e$$) in each molecule of $$H_{2}O$$, so
$$Q=14N_{A}q=14(6.02\times 10^{23})(10)(1.60\times 10^{-19}C)=1.3\times 10^{7}C$$.


SIMILAR QUESTIONS

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