Calculate the refractive index of glass with respect to water. It is given that refractive indices of glass and water with respect to air are $$\dfrac {3}{2}$$ and $$\dfrac {4}{3}$$ respectively.
In an experiment for determination of refractive index of glass of a prism by $$i-\delta\ plot$$ it was found that a ray incident at angle $${ 35 }^{ \circ }$$ suffers a deviation of $${ 40 }^{ \circ }$$ and that it emerges at angle $${ 79 }^{ \circ }.$$ In that case which of the following is closest to the maximum possible value of the refractive index?
For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index:
The angle of incidence for a ray of light at a refracting surface of a prism is $${45}^{o}$$. The angle of prism is $${60}^{o}$$. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are
For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index :
The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A/2). The angle of minimum deviation is :
For an isosceles prism of angle $$A$$ and refractive index $$\mu$$, it is found that the angle of minimum deviation $$\delta_m=A$$. Which of the following option(s) is/are correct?
The maximum refractive index of a prism which permits the passage of light through it, when the refractive angle of the prism is $${90^0}$$, is
When a ray of light falls on a prism, light gets dispersed because :
In the condition of minimum deviation position, a ray travels within the prism :
The refractive index of the material of prism, if a thin prism of angle $$A=6^o$$, produces a deviation $$\delta =3^o$$, is :