Single Choice

$$CH_3-CH_2-CH = CH_2+HBr\xrightarrow[]{ROOR(peroxide)} \underset{Major}{(X)} + \underset{Minor}{(Y)}$$ X and Y respectively are:

A$$BrCH_2-CH_2-CH=CH_2$$ and $$C_2H_5-CH(Br)-CH_3$$
B$$C_2H_5-CH_2-CH_2Br$$ and $$Br-CH_2-CH_2-CH=CH_2$$
C$$C_2H_5-CH_2-CH_2Br$$ and $$C_2H_5-CH(Br)-CH_3$$
Correct Answer
D$$C_2H_5CH(Br) -CH_3$$ and $$C_2H_5-CH_2-CH_2Br$$

Solution

CH3−CH2−CH=CH2+HBr
ROOR/peroxide
⟶
CH3−CH2−CH2−CH2Br(major) +
CH3−CH2−CH(Br)−CH3(Minor)


Anti-Markonikoff's rule: The negative part of the reagent will be added on to the carbon which is having more number of carbon atoms will be the major product.

Hence option C is correct.

SIMILAR QUESTIONS

Hydrocarbons

What is the major product expected from the following reaction? Where $$D$$ is an isotope of hydrogen.

Hydrocarbons

In the presence of peroxide, HCl and HI do not give anit-Markownikoff's addition to alkenes because:

Hydrocarbons

Which of the following will yield a mixture of 2-chlorobutene and 3-chlorobutene on treatment with $$\displaystyle HCl$$?

Hydrocarbons

In the reaction with $$HCl$$, an alkene reacts in accordance with the Markovnikov's rule to give a product 1-chloro-1-methylcyclohexane. The possible alkene is:

Hydrocarbons

In the above reaction, the major product is:

Hydrocarbons

How many structures of $$X$$ is possible?

Hydrocarbons

Arrange the following hydrogen halides in order of their decreasing reactivity with propene.

Hydrocarbons

Provide the structures of compounds A, B, C, and D in the above questions.

Hydrocarbons

Provide the structures of compounds A, B, C, and D in the above questions.

Hydrocarbons

Write the structure of the major organic product in each of the following reactions: $$CH_3CH=C(CH_3)_2+HBr \rightarrow$$

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