Single Choice

$$CH_{3}CH_{2}COOH \xrightarrow[Fe]{Cl_{2}} X\xrightarrow[KOH]{alc.}Y$$ The compound $$Y$$ is :

A$$CH_{3}CH_{2}OH$$
B$$CH_{3}CH_{2}CN$$
C$$CH_{2} = CHCOOH$$
Correct Answer
D$$CH_{2}=CHClCOOH$$

Solution

The complete reaction sequence is as follows:
$$CH_{3}CH_{2}COOH \xrightarrow[Fe]{Cl_{2}} CH_3CHClCOOH\xrightarrow[KOH]{alc.}CH_2=CHCOOH$$
$$Cl_{2} , Fe$$ causes halogenation, while alcoholic $$KOH$$ causes dehydrohalogenation.

SIMILAR QUESTIONS

Physical World

In the presence of a small amount of phosphorous, aliphatic carboxylic acids react with chlorine or bromine to yield a compound in which $$\alpha$$-hydrogen has been replaced by halogen. This reaction is known as:

Physical World

The following acids can be differentiated by:

Physical World

The reaction $$CH_3COOH+Cl_2\overset{P}{\rightarrow}ClCH_2COOH+HCl$$ is called :

Physical World

What are $$A$$ and $$B$$ in the following sequence of reactions (i) $$C{ H }_{ 3 }C{ H }_{ 2 }COOH\overset { P }{ \underset { { Br }_{ 2 } }{ \longrightarrow } } A$$ ; (ii) $$A \overset { (i) Alc\cdot KOH excess }{ \underset { (ii){ H }^{ + } }{ \longrightarrow } } B$$

Physical World

Hell-Volhard -Zelinsky reaction involves the replacement of an ------ atom from from the alkyl group of a monocarboxylic acid by a ------ atom.

Physical World

The reaction of chlorine on carboxylic acids to form alpha chloro acids is called as:

Physical World

State whether the following statement is True or False: HEll-Volhard-Zelinsky reaction is given by those acids which have $$\alpha$$ hydrogen atoms

Physical World

Which of the following will not undergo HVZ reaction?

Physical World

$${CH}_{3}{CH}_{2}COOH\xrightarrow [ Red\quad P ]{ { Cl }_{ 2 } } (A)\xrightarrow [ ]{ Alc.KOH } (B)$$ The compound (B) is:

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