Haloalkanes and Haloarenes
Ethyl chloride is converted to butane by :
Choose the incorrect reaction.
A. The reaction given in option A is correct. The preparation of higher alkanes from lower alkyl halides using sodium metal is called as Wurtz reaction. When two molecules of ethyl iodide are treated with sodium metal in the presence of diethyl ether as solvent, n-butane is formed.
B. The reaction given in option B is incorrect. When sodium metal in Wurtz reaction is replaced by zinc metal, then that reaction is called as Frankland reaction and it also gives a higher alkane as the product. Hence the product of the reaction given in option B should be n-butane.
C. Williamson synthesis of alkyl sulfides is carried out by treating alkyl halides with sodium sulfide. The reaction given in option C is correct.
D. When alkyl bromide is treated with NaI and acetone, then halogen exchange reaction takes place to give alkyl iodide as the product. This is called as Finkelstein reaction. Hence the reaction given in option D is also correct.
Ethyl chloride is converted to butane by :
Isopropyl bromide on Wurtz reaction gives:
Explain wurtz fitting reaction with example
Which one of the following compounds cannot be prepared by Wurtz reaction?
Which of the following alkane cannot be made in good yield by Wurtz reaction?
Which of the following halides can yield ethane and also methane in a single step?
How will you bring about the following conversions in not more than two steps? $$1-$$ Chlorobutane to $$n-$$octane
Convert the following: $$2$$-bromobutane to $$3, 4$$-dimethylhexane
How will you bring about the following conversions in not more than two steps? $$1-$$ Chlorobutane to $$n-$$octane
Give a brief account of the following with one example of each. Wurtz reaction.