Solution

Formation of $$(E)$$ suggests monosubstituted acid and reaction of 1 mol of $${H}_{2}$$ with (A) and (B) shows one $$(C=C)$$ bond. There are 6 D.U (4 D.U for $$(Ph)$$ group, 1 D.U for $$(COOH)$$ and 1 D.U for $$(C=C)$$ in both (A) and (B)
Chiral compound with nine $$C$$ atoms would be (given figure)
Here $$(C)$$ and $$(D)$$ can be distinguished quantitatively by H.V.Z reaction. $$(C)$$ has one $$\alpha$$- H atoms and would give dichlorinated product. The chlorine content in the chlorinated derivaties of $$(C)$$ and $$(D)$$ is determined by quantitative methods