Single Choice

Consider the molecules $$CH_{4}, NH_{3}$$ and $$H_{2}O$$. Which of the given statements is false?

AThe $$H-C-H$$ bond angles in $$CH_{4}$$, the $$H-N-H$$ bond angle in $$NH_{3}$$, and the $$H-O-H$$ bond angle in $$H_{2}O$$ are all greater than $$90^{\circ}$$
BThe $$H-O-H$$ bond angle in $$H_{2}O$$ is larger than the $$H-C-H$$ bond angle in $$CH_{4}$$
Correct Answer
CThe $$H-O-H$$ bond angle in $$H_{2}O$$ is smaller than the $$H-N-H$$ bond angle in $$NH_{3}$$
DThe $$H-C-H$$ bond angle in $$CH_{4}$$ is larger than the $$H-N-H$$ bond angle in $$NH_{3}$$

Solution

All the three molecules are $$sp^3$$ hybridised but the bond angles are different due to the presence of lone pair. The bond angle of $$H_2O$$ is $$104.5^o$$ due to bond pair - lone pair repulsion and the bond angle of $$CH_4$$ is $$109.25^o$$.

Hence, option B is a false statement.

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