Single Choice

Cube root of 1728

A11
B13
C12
Correct Answer
D14

Solution

$$\displaystyle 1728=2\times 2\times 2\times 2\times 2\times 2\times 3\times 3\times 3=\left( { 2 }^{ 3 }\times { 2 }^{ 3 }\times { 3 }^{ 3 } \right) $$
$$\displaystyle ={ \left( 2\times 2\times 3 \right) }^{ 3 }$$
1728 is a perfect cube.

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