Subjective Type

Determine the pH value of $$0.001 M$$ acetic acid solution if it is $$2$$% ionised at this concentration. How can the degree of dissociation of this acetic acid solution be increased?

Solution

$$c = 0.001 M$$

$$\left[ { H }^{ + } \right] =C\alpha $$
$$= 0.001\times 2$$
$$= 0.002 $$

pH $$= - \log { \left[ { H }^{ + } \right] }$$
$$= -\log { \left[ 0.002 \right] }$$

$$ \ { pH=2.69897 } $$

SIMILAR QUESTIONS

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