Subjective Type

$$\displaystyle{ a }_{ n }={ 2 }^{ n }$$

Solution

Given, $$\displaystyle { a }_{ n }={ 2 }^{ n }$$
Substituting $$n =1, 2, 3, 4, 5$$ we obtain
$${ a }_{ 1 }={2}^{1} =2,\\
{a }_{ 2 }={2}^{2} =4,\\
{ a }_{ 3 }={2}^{3} =8,\\
{ a }_{ 4 }={2}^{4} =16,\\
{ a }_{ 5 }={2}^{5} =32$$

SIMILAR QUESTIONS

Sequences and Series

Given an A.P. whose terms are all positive integers. The sum of its first nine terms is greater than $$200$$ and less than $$220$$. If the second term in it is $$12$$, then $$4^{th}$$ term is :

Sequences and Series

Let X be the set consisting of the first $$2018$$ terms of the arithmetic progression $$1, 6, 11,$$______, and Y be the set consisting of the first $$2018$$ terms of the arithmetic progression $$9, 16, 23$$, ________. Then, the number of elements in the set X$$\cup$$Y is _______?

Sequences and Series

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Sequences and Series

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$$\displaystyle{ a }_{ n }=n\frac { { n }^{ 2 }+5 }{ 4 } $$

Sequences and Series

$$\displaystyle{ a }_{ n }=4n-3;{ a }_{ 17 },{ a }_{ 24 }$$

Sequences and Series

$$\displaystyle { a }_{ n }=\frac { { n }^{ 2 } }{ { 2 }^{ n } } ;{ a }_{ 7 }$$

Sequences and Series

$$\displaystyle{ a }_{ n }=({ -1 })^{ n-1 }{ n }^{ 3 };{ a }_{ 9 }$$

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