Periodic Classification of Elements
The third ionization enthalpy is minimum for :
Explain the following statement: "The first ionization energy of carbon atom is greater than that of boron atom, whereas the reverse is true for the second ionization energy".
From left to right in the periodic table, the ionization energy increases; therefore, the first ionization energy of carbon atom is greater than that of boron.
The second ionization energy of boron is greater than that of carbon because after losing one electron, boron acquires a stable electronic configuration.
$$B(z = 5) : 1s^2 2s^22p^1$$.
$$B^+ : 1s^2 2s^2$$
The third ionization enthalpy is minimum for :
The first ionization energy (in kJ/mol) of Na, Mg, Al and Si respectively, are:
Which of the following represents the correct order of increasing first ionization enthalpy for $$Ca$$, $$Ba$$, $$S$$, $$Se$$ and $$Ar$$?
In which of the following options the order of arrangement does not goes with the variation of property indicated against it?
Compare the alkali metals and alkaline earth metals with respect to (i) ionisation enthalpy (ii) basicity of oxides and (iii) solubility of hydroxides.
In the periodic table, the maximum chemical reactivity is at the extreme left (alkali metals) and extreme right (halogens). Which properties of these two groups are responsible for this?
The element having very high ionization enthalpy but zero electron gain enthalpy is :
The first ionisation potential of $$Na, Mg, Al$$ and $$Si$$ are in the order:
In which of the following transformation least energy is required?
Which of the following electronic configuration is associated with the biggest jump between the second and third ionization energies?