Single Choice

$$[Fe(H_{2}O)_{6}]^{2+}$$ and $$[Fe(CN)_{6}]^{4-}$$ differ in

AGeometry, magnetic moment
BMagnetic moment, colour
CGeometry, hybridisation
Correct Answer
DHybridisation, number of unpaired electrons

Solution

Given $${ \left[ { Fe\left( { H }_{ 2 }O \right) }_{ 6 } \right] }^{ +2 }$$ and $${ \left[ { Fe\left( CN \right) }_{ 6 } \right] }^{ 4- }$$
These compound differ each other because $$(CN)$$ ligand is a strong ligand it pair up with unpaired electrons in the outermost shell where as $${ H }_{ 2 }O$$ is a weak ligand.
So different in colour and magnetic moment.
Also, $$[Fe(H_2O)]^{2+}$$ shows $$sp^3d^2$$ hybridization and $$[Fe(CN)_6]^{4-}$$ shows $$d^2sp^3$$ hybridization.
Since $$[Fe(H_2O)]^{2+}$$ is high spin complex and $$[Fe(CN)_6]^{4-}$$ is low spin complex, they have different number of unpaired electrons.

SIMILAR QUESTIONS

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The most stable complex ion is:

Coordination Compounds

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Coordination Compounds

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Coordination Compounds

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Coordination Compounds

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Coordination Compounds

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