Single Choice

For the myopic eye, the defect is cured by

AConvex lens
BConcave lens
Correct Answer
CCylindrical lens
DToric lens

Solution

In myopia, $$\displaystyle u=\infty ,v=d=$$ distance of far point
By $$\displaystyle \frac { 1 }{ F } =\frac { 1 }{ v } -\frac { 1 }{ u } $$, we get $$\displaystyle f=-d$$
Since f is negative, hence the lens used is concave.

SIMILAR QUESTIONS

Optics

Does short-sightedness (myopia) or long-sightedness (hypermetropia) imply necessarily that the eye has partially lost its ability of accommodation? If not, what might cause these defects of vision?

Optics

A defective eye cannot see close objects clearly because their image is formed:

Optics

Identify the wrong description of the given figures.

Optics

Match the list I with the List II for the combination shown Presbiopia Sphero-cylindrical lens Hypermetropia Convex lens of proper power may be used close to the eye Astigmatism Concave lens of suitable focal length Myopia Bifocal lens of suitable focal length

Optics

To remove myopia ( short sightedness ) a lens of power $$0.66\ D$$ is required. The distant point of the eye is approximately

Optics

A person is suffering from 'presbyopia' ( myopia and hyper metropia both defects ) should use

Optics

A student sitting at the back of the classroom cannot read clearly the letters written on the blackboard. What advice will a doctor give to her? Draw ray diagram for the correction of this defect.

Optics

When do we consider a person to be myopic or hypermetropic? Explain using diagrams how the defects associated with myopic and hypermetropic eye can be corrected?

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