Single Choice

For the reaction, $${ C }_{ 2 }{ H }_{ 5 }OH+HX\underrightarrow { \quad \quad Zn{ X }_{ 2 }\quad \quad } { C }_{ 2 }{ H }_{ 5 }X$$, the order of reactivity is:

A$$HI$$ > $$HCl$$ > $$HBr$$
B$$HI$$ > $$HBr$$ > $$HCl$$
Correct Answer
C$$HCl$$ > $$HBr$$ > $$HI$$
D$$HBr$$ > $$HI$$ > $$HCl$$

Solution

As we know,
bond strength are in order of
$$H-Cl > H-Br > H-I$$
so reactivity order is
$$HI$$ > $$HBr$$ > $$HCl$$

SIMILAR QUESTIONS

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