Chemistry Practical
A bromide ion does not interfere with the chromyl chloride test, because when a bromide is present :
Give the correct order of initials T or F for following statements. Use T if statement is true and F if it is false. (i) $$Cu^+$$ undergoes disproportionation to $$Cu$$ and $$Cu^{2+}$$ in aqueous solution. (ii) $$Hg_2Cl_2$$ does not impart chromyl chloride test. (iii) Sulphide ions react with sodium nitroprusside to form a purple coloured complex. In this reaction, oxidation state of iron changes.
Sulphide ions react with sodium nitroprusside to form a purple coloured complex.
Reaction:
$$Na_2S + Na_2[Fe(CN)_5]NO\rightarrow Na_4[Fe(CN)_5]NOS$$(purple colour)
Chromyl chloride test is given by ionic chlorides only. Chloride of $$Hg^+$$does not respond to chromyl chloride test due to covalent character, which allows to ionise only slightly.
In an aqueous medium, $$Cu^{2+}$$ is more stable than $$Cu^+$$. This is because although energy is required to remove one electron from $$Cu^+$$ to $$Cu^{2+}$$, high hydration energy of $$Cu^{2+}$$ compensates for it.
Therefore, $$Cu^+$$ ion in an aqueous solution is unstable. It disproportionates to give $$Cu^{2+}$$ and $$Cu$$.
$$2Cu^+ \rightarrow Cu+ Cu^{+2}$$
So all statements are correct.
Option D is correct.
A bromide ion does not interfere with the chromyl chloride test, because when a bromide is present :
A salt, when warmed with zinc powder and an $$NaOH$$ solution, gives a gas that turns a filter paper soaked with an alkaline solution of $$K_2[HgI_4 ]$$ brown. The salt responds to the brown ring test when acetic acid is used in place of sulphuric acid. The anion present in the salt is :
An organic compound (A) on heating produces two gases (B) and (C) and neutral oxide (D) which turns cobalt chloride paper pink. Gas (B) turns lime water milky and produces an acidic solution, with water. Gas (C) produces a poisonous gas (E) with chlorine gas, this gas with ammonia gives an organic compound (F) which on further reaction with (D) gives $$NH_3$$ gas. Then, compounds (A) and (F) can be found as:
Match the following. (I) $$HCO_2^-$$ (P) Obtained through Solvay's process (II) $$K_2CO_3$$ (Q) Green colouration due to $$[Cr(H_2O)_6]^{3+}$$ ion (III) $$S_2O_3^{2-} + FeCl_3$$ solution (R) Reduces $$[Cu(C_4H_4O_6)_2]^{2-}$$ to red ppt. (IV) $$SO_2^{3-} + K_2 Cr_7 O_7 / H^+$$ (S) Green colouration (V) $$Na_2 CO_3$$ (T) Melts at 850 $$^o$$C
Which of the following statement is incorrect? (I) In S2O 2− 3 both sulphur are different in nature. (II) Sodium acetate and lead acetate on heating giving the same type of product, whereas Mn, Sn, Fe oxalate salt giving different types of products. (Ill)Aqueous solution OCl−,S2− and CO 2− 3 basic in nature. (IV)NO − 2 oxidises I− whereas Br2 and Cl2 oxidises NO − 2
(A) + NaCl $$\rightarrow$$ (B) (white ppt.) (B) + KI $$\rightarrow$$ (C) (green ppt.) (C) + $${\underset {(\text{excess})}{KI}} \rightarrow$$ (D) + (E) (colorless solution) (E) + $$NH_3$$ + KOH $$\rightarrow$$ (F) When compound (A) reacts with $$Na_2CrO_4$$ solution, the color of the compound formed is________.
When colourless solution (C) reacts with $$Pb_3O_4/H^+$$, it acquires a violet red colour due to formation of__________.
The structure of compound (A) is:
The brown solution obtained in (i) is due to_________.
Which of the following reactions takes place in (ii)?