Single Choice

$${H}_{3}{PO}_{4}$$ is a tribasic acid and one of its salt is $$Na{H}_{2}{PO}_{4}$$. What volume of $$1M$$ $$NaOH$$ solution should be added to $$12g$$ of $$Na{H}_{2}{PO}_{4}$$ to convert it into $${Na}_{3}{PO}_{4}$$?

A$$100mL$$
B$$200mL$$
Correct Answer
C$$80mL$$
D$$300mL$$

Solution

NaH2PO4→Na3PO4

n−factor=2 because 2H+ are removed from NaH2PO4

meq of acid = meq of base

12
120/2

×1000=V×1×1
100
5

=V
V=20ml

Option B is correct.

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