Periodic Classification of Elements
AB is predominantly ionic as $$\displaystyle A^{+}B^{-}$$ if___________.
HAO is the compound whose aqueous solutions is basic and order of basic strength is____.
As per Gallis, in $$AOH$$
(i) if electronegativity of A is more than 1.7 (Non-metal) then it is acidic in nature.
(ii) if electronegativity of 'A' is less than 1.7 (metal) then $$AOH$$ will be basic in nature.
So $$COH$$ is basic in nature as it has very low electronegativity (1.6).
and basic strength is $$HCO > HAO$$.
Hence, the correct option is $$\text{C}$$
AB is predominantly ionic as $$\displaystyle A^{+}B^{-}$$ if___________.
Element Electronegative $$P$$ 2.1 $$H$$ 2.2 $$Br$$ 2.8 $$O$$ 3.5 On the basis of the electronegativity values given above, in which of the following are the bonds most polar?
Bond polarity of diatomic molecule is because of:
Identify the correct order of solubility in aqueous medium :
Aqueous solutions of two compounds $$M-O-H$$ and $$M'-O-H$$ have been prepared in two different beakers. If the electronegativity of $$M= 3.5,\ M' = 1.72,\ O = 3.0$$ and $$H = 2.1$$, then the solutions respectively are:
Aqueous solutions of two compounds $$M_1 -O-H$$ and $$M_ 2-O-H$$ are prepared in two different beakers. If, the electronegativity of $$M, =3.4,M.2 =1.2,O =3.5$$ and $$H =2.1$$, then the nature of two solutions will be respectively :
Water is an oxide of hydrogen represented by the formula $$H_2O$$. However, the oxide of fluorine is represented by the formula $$OF_2$$ and not $$F_2O$$. How do you justify this?
Two elements having equal electronegative values will form covalent (non polar) bond. If true enter 1, else enter 0.
On the basis of percent ionic character for the compounds $$CD$$ & $$AB$$, they will be colourless. If true enter 1, else enter 0.
Calculate the electronegativity of silicon using Allred Rochow method. Covalent radius of silicon is 1.175 $$ \overset{o}{A} .$$