Solution

$$\underset {propanoic\ acid}{CH_{3}CH_{2}.COOH} + NH_{3} \rightarrow CH_{3}CH_{2}COONH_{4}\underset {-H_{2}O}{\xrightarrow {\Delta}}CH_{2}CH_{2}CONH_{2}$$
$$\underset {\Delta}{\xrightarrow {Br_{2} + 4NaOH}} \underset {ethyl\ amine}{CH_{3}CH_{2}NH_{2}} + Na_{2}CO_{3} + 2NaBr + 2H_{2}O$$