Single Choice

Hydrogen bonds are formed in many compounds e.g., $$H_2O, HF \ and \ NH_3$$. The boiling point of such compounds depends to a large extent on the strength of the hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points of the above compounds is :

A$$HF > H_2O > NH_3$$
B$$H_2O > HF > NH_3$$
Correct Answer
C$$NH_3 > HF > H_2O$$
D$$NH_3 > H_2O > HF$$

Solution

Strength of hydrogen bonding depends on the size and electronegativity of the atom.

Smaller the size of the atom, greater is the electronegativity and hence stronger is the $$H-$$bonding. Thus, the order of strength of H-bonding is $$H...F > H...O > H...N$$.

But each $$HF$$ molecule is linked only to two other $$HF$$ molecules while each $$H_2O$$ molecule is linked to four other $$H_2O$$ molecules through $$H-$$bonding.

Hence, the decreasing order of boiling points is $$H_2O > HF > NH_3$$.

Hence, the correct option is B.


SIMILAR QUESTIONS

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Chemical Bonding

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Which of the following has strongest bond?

Chemical Bonding

Among NH3,H2O,HF and H2S which have the highest magnitude of hydrogen bonding?

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