If $$4\ g$$ of oxygen diffuse through a very narrow hole, how much hydrogen would have diffused under identical conditions?
The rate of diffusion is inversely proportional to the square root of molar mass.
$$\dfrac {W_{O_2}}{W_{H_2}}=\sqrt {\dfrac {M_{H_2}}{W_{O_2}}}$$
The molecular weights of hydrogen and oxygen are $$2$$ g/mol and $$32$$ g/mol respectively.
Substitute values in the above expression.
$$\dfrac {4}{W_{H_2}}=\sqrt {\dfrac {2}{32}}=\dfrac {1}{4}$$
$$W_{H_2}=4\times 4=16 $$ g
Hence, $$16$$ g of hydrogen would have diffused under identical conditions.
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Rate of diffusion of a gas is