Solutions
A non ideal solution was prepared by mixing 30ml chloroform and 50ml acetone. The volume of mixture will be :
In a mixture A and B components show negative deviation as :
In a mixture A and B components show negative deviation as $$\Delta H_{mixing}=-ve$$
For negative deviation $$\Delta V_{mixing}=-ve, \Delta H_{mixing}=-ve$$
If the force of attraction between molecular of and A and B in the solution are stronger than that of between A A and B B, then the tendency of escaping of molecules AB from the solution becomes less than that of pure liquids.
The total pressure of the solution will be lower than the corresponding vapour pressure of ideal solution of the same component A and B. This type of solution shows negative deviation from Raoult's law.
Hence, option (B) is correct.
A non ideal solution was prepared by mixing 30ml chloroform and 50ml acetone. The volume of mixture will be :
Total vapour pressure of mixture of 1 mol of A $$\left ( P^{0}_{A}=150 \ torr \right )$$ and 2 mol of B $$\left ( P^{0}_{B}=240 \ torr \right )$$ is 200 torr. In this case :
The azeotropic mixture of water and $$HCl$$ boils at $$108.5^{0}C$$ . This solution is:
State True or False. $$CHCl_3$$ and acetone mixture shows negative deviation from Raoult's law.
A solution of sulphuric acid in water exhibits :
Which of the following solutions is an example of negative deviation from Raoult's law?
When acetone and chloroform are mixed together, hydrogen bonds are formed between them. Which of the following statements is correct about the solution made by mixing acetone and chloroform ?
State Raoult's law for a solution containing non-volatile solute. What type of deviation from Raoult's law is shown by a solution of chloroform and acetone and why?
Define azeotropes. What type of azeotropes is formed by negative deviation from Raoult's law? Give an example.
Answer the following question : In non-ideal solution, what type of deviation shows the formation of maximum boiling azeotropes?