Single Choice

In a single slit diffraction with $$\displaystyle \lambda =500nm$$ and a lens of diameter 0.1 mm, width of central maxima, obtain on screen at a distance of 1 m will be

A$$5 mm$$
B$$1 mm$$
C$$10 mm$$
Correct Answer
D$$2.5 mm$$

Solution

Angle subtended by two minima at the slit in a single slit diffraction $$=\alpha=\dfrac{2\lambda}{w}$$
where, $$w$$ is the slit width.
Here the lens' diameter would act as slit width.
The width of central maxima is the distance between the two minima $$=d\alpha$$
where, $$d$$ is the distance between slit and screen $$=1\ m$$
Thus, the width of central maxima $$=10\ mm$$


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