Subjective Type

Not considering the electronic spin, the degeneracy of the second excited state $$\left(n=3\right)$$ of $$H$$-atom is $$9$$, while the degeneracy of the second excited state of $${H}^{-}$$ is _______.

Solution

$${H}^{-}$$ is a multielectron species. Hence, it will follow $$\left(n+l\right)$$ rule.
$${H}^{-} \left(2e\right) \longrightarrow 1{s}^{2} 2{s}^{0} 2{p}^{0}$$ (ground state)
$$\longrightarrow 1{s}^{1} 2s 2{p}^{1}$$ (second excited state)

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