Single Choice

On passing a current through $$KCl$$ solution $$19.5\ g$$ of potassium is deposited. If the same quantity of electricity is passed through a solution of aluminium chloride, the amount of aluminium deposited is

A$$4.5\ g$$
Correct Answer
B$$9.0\ g$$
C$$13.5\ g$$
D$$27\ g$$

Solution

ccording to Faradays second law of electrolysis, the amount of different substances deposited by the passage of same quantity of electricity are proportional to their chemical equivalent weights.
$$ W∝E$$\dfrac{ W1}{W2}=\dfrac{E1}{E2}$$W_{KCl}=19.5g$$;
$$E_{K+}=39 W_{AlCl3}=?$$;
$$E_{Al^{3+}}=\dfrac{27}{3}=9$$
then ,
$$ \dfrac{19.5}{x}=\dfrac{39}{9 }x=\dfrac{19.5×9}{39}=4.5g $$
So, $$4.5$$ g of aluminium is deposited.

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