Single Choice

One mole of an ideal monoatomic gas at temperature $$T_o$$ expands slowly according to the law $$\dfrac{P}{V}= constant$$. If the final temperature is $$2T_o$$, heat supplied to the gas is:

A$$ 2R T_o$$
Correct Answer
B$$ \dfrac{3}{2}R T_o$$
C$$ R T_o$$
D$$ \dfrac{1}{2}R T_o$$

Solution

As given,
$$\dfrac{P}{V}=PV^{-1}=constant$$
Hence, polytropic exponent is $$-1$$
In a polytropic process,
$$\Delta Q = \Delta U + W=( \dfrac{R}{\gamma -1}- \dfrac{R}{\eta -1})\Delta T$$ where $$\eta= -1$$ is the polytropic exponent.
$$ \therefore \Delta Q = R(\dfrac{1}{\dfrac{5}{3}-1}- \dfrac{1}{-1-1})(2T_0 - T_0)=2RT_0$$


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