Single Choice

Polar molecule among the following is:

A$$N_{2}$$
B$$H_{2}O$$
Correct Answer
C$$CH_{4}$$
D$$CO_{2}$$

Solution

Water is polar molecule
Electronegativity Difference Type of Bond Formed




0.0 to 0.2 nonpolar covalent
0.3 to 1.4 polar covalent
> 1.5 ionic
The electronegativity difference provides a way of predicting the kind of bond that will form between two elements. If the difference is between $$0.5 -1.4$$ then the bond formed is polar covalent.
$$N_2$$ Electron negativity difference $$= 3.0-3.0 = 0$$ Bond $$= $$Non-polar covalent
$$H_2O$$ Electron negativity difference $$= 2.1-3.5 = 1.4$$ Bond $$=$$ Polar covalent
$$CH_4$$ Electron negativity difference $$= 2.1-2.5 = 0.4$$ Bond $$= $$ Non-polar covalent
$$CO_2$$ Electron negativity difference $$= 2.5-3.5 = 1.0$$ Bond $$= $$Non-polar covalent
$$KCl$$ Electron negativity difference $$= 0.8-3.0 = 2.2$$ Bond $$=$$ Ionic

SIMILAR QUESTIONS

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