Optics
The size of the image, if an object of $$2.5$$m height is placed at a distance of $$10$$ cm from a concave mirror is: (Take radius of curvature of concave mirror $$=30$$ cm)
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Single Choice
Rays from Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to the size of the object ?
A15 cm in front of the mirror
B30 cm in front of the mirror
Correct Answer
Cbetween 15 cm and 30 cm in front of the mirror
Dmore than 30 cm in front of the mirror
Solution
The ray diagram illustrates that, in case of a concave mirror, the image size becomes equal to the object size when the object distance equals the radius of curvature, i.e, twice the focal length.
So, the object has to be placed at a distance of $$(15 \times 2) = 30\ cm$$ in front of the concave mirror.
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